• ghariksforge@lemmy.world
        link
        fedilink
        arrow-up
        11
        arrow-down
        2
        ·
        1 year ago

        It’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.

        • RatMaster@sh.itjust.works
          link
          fedilink
          arrow-up
          11
          ·
          1 year ago

          You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂

          • Patawagon@lemmy.world
            link
            fedilink
            arrow-up
            4
            ·
            1 year ago

            I wonder if we do stack it till every human is tied to the track whos at the lever?

            Does the train/AI decide?

            • fneu@discuss.tchncs.de
              link
              fedilink
              English
              arrow-up
              3
              ·
              1 year ago

              The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group…

        • Sabazius@lemmy.world
          link
          fedilink
          arrow-up
          10
          ·
          edit-2
          1 year ago

          It’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)

          • Magikjak@lemmy.world
            link
            fedilink
            arrow-up
            1
            ·
            1 year ago

            I think you have to include 2^0 for that to be true?

            e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.